একটা সংখ্যার বেস দেওয়া থাকবে, ঐ বেসে ১ থেকে ৩০০ এর মঝে যত প্যালিন্ড্রমিক (সংখ্যাটির বর্গের) নাম্বার আছে সেগুলা প্রিন্ট করতে হবে।Palindromic Squares
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#include <bits/stdc++.h> | |
using namespace std; | |
#define INF 1<<30 | |
#define MAX 10005 | |
#define FASTIO ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0); | |
typedef long long ll; | |
/* | |
ID: hasanma1 | |
TASK: palsquare | |
LANG: C++ | |
*/ | |
char value[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J'}; | |
string Base(int n, int base) | |
{ | |
string t; | |
while(n != 0){ | |
t = value[n % base] + t; | |
n /= base; | |
} | |
// cerr << t << endl; | |
return t; | |
} | |
int main() | |
{ | |
FASTIO | |
/* | |
//double start_time = clock(); | |
#ifndef ONLINE_JUDGE | |
freopen("in.txt", "r", stdin); | |
freopen("out.txt", "w", stdout); | |
freopen("error.txt", "w", stderr); | |
#endif | |
//*/ | |
///* | |
ofstream cout ("palsquare.out"); | |
ifstream cin ("palsquare.in"); | |
//*/ | |
int base; | |
cin >> base; | |
//cerr << base<<endl; | |
for(int i = 1; i <= 300; i++){ | |
//cerr << i+i << endl; | |
string N = Base(i, base); | |
string sq = Base(i*i, base); | |
string _new = sq; | |
reverse(_new.begin(), _new.end()); | |
if(sq == _new){ | |
cout << N << " "<<sq<<"\n"; | |
} | |
} | |
//double end_time = clock(); | |
//printf( "Time = %lf ms\n", ( (end_time - start_time) / CLOCKS_PER_SEC)*1000); | |
return 0; | |
} |
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