Counting Sort
Counting Sort
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/// O(n+k)-(input+range) | |
#include<bits/stdc++.h> | |
using namespace std; | |
#define N 255 | |
void countSort(char ar[]) | |
{ | |
char output[strlen(ar)]; | |
int cnt[N + 1], i; | |
memset(cnt,0,sizeof(cnt)); | |
for(int i = 0; ar[i]; i++) | |
++cnt[ar[i]]; | |
for(int i = 1; i <= N; i++) | |
cnt[i] += cnt[i-1]; | |
for(int i = 0; ar[i]; i++){ | |
output[cnt[ar[i]] - 1] = ar[i]; | |
--cnt[ar[i]]; | |
} | |
for(int i = 0; ar[i]; i++) | |
ar[i] = output[i]; | |
} | |
int main() | |
{ | |
char ar[] = "thankstogeeksforgeeks"; | |
countSort(ar); | |
cout << ar << endl; | |
return 0; | |
} |
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/// its work negative number also | |
#include<bits/stdc++.h> | |
using namespace std; | |
void countSort(vector<int>& ar) | |
{ | |
// cout << "Enter--------\n"; | |
int mx = *max_element(ar.begin(), ar.end()); | |
int mn = *min_element(ar.begin(), ar.end()); | |
// cout << mx << " "<<mn << endl; | |
int N = mx - mn + 1; | |
//cout << N << endl; | |
vector<int> cnt(N), output(ar.size()); | |
for(int i = 0; i < ar.size(); i++){ | |
// cout << ar[i] - mn << " "<< ar[i] << " "<<mn<<endl; | |
cnt[ ar[i] - mn ]++; | |
} | |
for(int i = 1; i <= cnt.size(); i++) | |
cnt[i] += cnt[i-1]; | |
for(int i = ar.size() - 1; i >= 0; i--){ | |
output[ cnt[ar[i] - mn] - 1] = ar[i]; | |
cnt[ar[i] - mn]--; | |
} | |
for(int i = 0; i < ar.size(); i++) | |
ar[i] = output[i]; | |
} | |
void print(vector<int>& v) | |
{ | |
for(int i = 0; i < v.size(); i++) | |
cout << v[i]<< " "; | |
cout << endl; | |
} | |
int main() | |
{ | |
vector<int> ar = {-5, -10, 0, -3, 8, 5, -1, 10}; | |
countSort(ar); | |
print(ar); | |
return 0; | |
} |
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