Merge Sort: Counting Inversions
Concept:
Count Inversions in an array
Implementation:
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/// O(NlogN) | |
#include<bits/stdc++.h> | |
using namespace std; | |
#define LL long long | |
int n; | |
void print(int ar[]) | |
{ | |
for(int i = 0; i < n; i++) | |
{ | |
cout << ar[i] << " "; | |
} | |
cout << endl; | |
} | |
long long ans = 0; | |
void merge(int a[], int i, int j) | |
{ | |
int mid = ((i+j)/2) + 1, X = j + 1; | |
int s = i; | |
int *arr = new int [j - i + 1]; | |
j = mid; | |
int k = 0; | |
while(i < mid && j < X) | |
{ | |
if(a[i] <= a[j]) | |
{ | |
arr[k] = a[i]; | |
i++; | |
} | |
else | |
{ | |
arr[k] = a[j]; | |
ans += (mid - i); | |
j++; | |
} | |
k++; | |
} | |
for(; i < mid; i++,k++) arr[k] = a[i]; | |
for(; j < X; j++, k++) arr[k] = a[j]; | |
for(k = 0; s < X; s++, k++)a[s] = arr[k]; | |
delete [] arr; | |
} | |
void merge_sort(int a[], int i, int j) | |
{ | |
if(i < j) | |
{ | |
int mid = (i + j)/2; | |
merge_sort(a,i,mid); | |
merge_sort(a,mid+1, j); | |
merge(a,i,j); | |
} | |
} | |
int main() | |
{ | |
// freopen("in.txt", "r", stdin); | |
int T; | |
scanf("%d", &T); | |
while(T--) | |
{ | |
ans = 0; | |
scanf("%d", &n); | |
int *ar = new int [n]; | |
for(int i = 0; i < n; i++) | |
{ | |
scanf("%d", &ar[i]); | |
} | |
merge_sort(ar,0,n-1); | |
cout << ans << endl; | |
// print(ar); | |
} | |
return 0; | |
} | |
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